Question

a can do a piece of work in 24 hours while B alone can do it in 16 hours if a b c working together can finish it in 8 hours in how many hours will see alone finish the work​

Answer 1

Answer:

48 days

Explanation:

piece of work done by A in one hour = 1/24

piece of work done by B in one hour = 1/16

piece of work done by A and B together in one hour= 1/24 +1/16

                                                                     = 5/48

piece of work done by A ,B and C together in one hour = 1/8

piece of work done by C in one hour= 1/8 - 5/48

                                                              = 1/48

Days taken by C to complete the work = 1/(1/48)

                                                                = 48 days          

Answer 2

we know that,

Number of hours A required to do piece of work = 24 hours

Number of hour B required to do piece of work = 16 hours

Let us consider number of hours C required to do piece of work = x hours

Number of hours A,B and C together required to do piece of work = 8 hours

∴ We can calculate, work done by A in 1 hour = 1/24

Work done by B in 1 hour = 1/16

Work done by C in 1 hour = 1/x

Work done by A, B and C together in a one hour = 1/8

Now, work done by A,B and C together in 1 hour= 1/24 + 1/16 +1/x

= 5/48 + 1/x 5/48 + 1/x

= 1/8 (5x+48)/48x

= 1/8 40x + 384

= 48x 8x = 384 x = 384/8 = 48

∴ C can do the work in 48 hours.