Question

A can do a piece of work in 25 days and and B can finish it in 20 days. they work together for 5 days and then A goes away. in how many days will B finish the remaining work

Answer 1

b finish 11 days remaining work.

a = 25
b= 20
LCM of a&b is 100
then one day work of a is 4
and one day work of b is 5
and both work in a day is = 9
both work together are 5 day so 5*9= 45
our total work is 100
100-45= 55 is our remaining work
now b is work in one day is 5
and remaining work is 55
55÷5=11 days is your answer.