A can do a piece of work in 25 days and B can finish it in 20days. They work together for five days and then A goes away. In how many days will B finish the remaining work????? Please let me know the answer.
Answers
Answered by
1
Answer:
EXPERT VERIFIED
Explanation:
A's 1 day's work =
25
1
Similarly, B's 1 day's work =
20
1
A's and B's together 1 day's work
25
1
+
20
1
=
100
4
+
100
5
=
100
4+5
=
100
9
Their 5 day's work together = 5 x 1 day's work
1−
100
45
=
100
100
−
100
45
=
100
100−45
=
100
55
Now, this remaining work is done by B.
Let B takes x days to complete it.
20
1
×x=
100
55
⇒x=
100
55
×20
⇒x=
5
55
⇒x=11
Hence, B will finish the remaining work in 11 days.
Similar questions