Question

a can do a piece of work in 25 days.which b alone can complete in 20 days. a started the work and was joined by b 10 days later the work lasted for

Answer 1

Answer:

In one day A can complete 1/25 of the work. And.

In one day B can complete 1/20 of the work.

Together they can complete 1/25+ 1/20 work in one day.

Hence in 5 days they can complete 5/25 + 5/20 work. ie = 9/20 work.

Remaining work is 1–9/20 work= 11/20 work

Hence B can complete the remaining 11/20 work in 11/20 / 1/20=11 days.

Step-by-step explanation:

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Answer 2

Answer:

Answer = 16 (2/3) days

Explanation:

Work done by A in l0 days = (1/25) *10 = 2/5

Remaining work = 1 - (2/5) = 3/5

(A+B)s 1 days work = (1/25) + (1/20) = 9/100

9/100 work is done by them in 1 day.

hence 3/5 work will be done by them in (3/5)*(100/9)

= 20/3days.

Total time taken = (10 + 20/3) = 16*(2/3) days