A can do a piece of work in 30 days and B can do it in 20 days. They work together for 4 days and then B leaves the job. In how many days, will A finish the remaining work?
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Answered by
1
Answer:
Work of A per day is 1/20
Work of B per day is 1/30
Together in 7 days is
7/20 +7/30=(21+14)/60=35/60
Balance work is 25/60=5/12
C can do 5/12 work in 10 days
Full work =(12/5)*10=24 days
Answered by
2
Step-by-step explanation:
Given:-
A can do a piece of work in 30 days and B can do it in 20 days. They work together for 4 days and then B leaves the job
To Find:-
Number of days, A will finish the remaining work
Solution:-
A's 1 day's work = 1/30
B's 1 day's work = 1/20
(A + B)'s 1 day's work = 1/30 + 1/20 = 2 + 3/60 = 5/60 = 1/12
(A + B)'s 4 day's work = 1/12 × 4 = 1/3
Remaining work = 1 - 1/3 = 3 - 1/3 = 2/3
Time taken by A to finish the remaining work = 2/3 ÷ 1/30
→ 2/3 × 30
→ 20 days
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