Question

A can do a piece of work in 60 days, Which B can do in 40 days. Both started the work but A left 10 days before the completion of the work. In how many days the work was completed? *

Answer 1

Answer:

Answer is 30.67 days. Therefore, together they take 24 days to complete the work. Now, if A left 10 days before completion then, Number of days A & B worked together = 24-10 = 14 days.

Step-by-step explanation:

hope this answer help u

FOLLOW ME

MARK AS BRAINLIST

Answer 2

||✪✪ GIVEN ✪✪||

• A can do a piece of work in 60 days.
• B can do in 40 days.
• A left 10 days before the completion of the work ...

|| ✰✰ ANSWER ✰✰ ||

→ LCM of 60 and 40 = 120 units = Let Total work.

So,

→ A per day work = (120/60) = 2 units.

→ B per day work = (120/40) = 3 units.

Now, Given That, A left 10 days before The completion of the work.

That Means in Last 10 days only B alone completed the rest work.

→ in Last 10 days be Did = 3*10 = 30 units of work.

__________

Left work = 120 - 30 = 90 units .

So, we can say That, This work was done by now A + B both ..

So, They will take = 90/(2+3) = 18 days.

Hence, Total Number of days to complete the work = 18 +10 = 28 days. (Ans).