Question

Divide the sum of 7/3 and 7/4 by their difference

Answer 1

$sum \: of \: \\ \frac{7}{3} + \frac{7}{4} \\ = \frac{28 + 21}{12} \\ = \frac{49}{12} \\ difference \: of \\ \frac{7}{3} - \frac{7}{4} \\ = \frac{28 - 21}{12} \\ = \frac{7}{12} \\ now \: we \: will \: Divide \: the \: sum \: of \: 7/3 \: and \: 7/4 \: by \: their \: difference \\ \frac{49}{12} \div \frac{7}{12} \\ = \frac{49}{12 } \times \frac{12}{7} \\ = 7$

Answer 2

here is Ur answer......