Math, asked by alishi6028, 11 months ago

If a2+b2+c2=41 and a+b+c = 9 find ab+bc+ca

Answers

Answered by shalini271226
6

here is ur answer.......

Attachments:
Answered by suveda34
3

Answer:

(a+b+c)^2 = a^2 + b^2 + c^2 + 2 ( ab + bc + ca )

consider ab + bc + ca = x

9 ^2 = 41 + 2 (x )

81 = 41 + 2x

81 - 41 = 2x

40 = 2x

x = 20

therefore ab+bc+ca = 20

hope it helps

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