A can do a piece of work in 60days working 14 hours. B has the same efficiency as of
a. A and b started working together. A works 5,6,7 and 8 hours respectively on first four days and repeats the cycle again. Then b has to work how many hours daily if they together completed the work in 80 days?
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Answer:
B has to work 4 hrs daily
Step-by-step explanation:
Number of rs required by A to complete work = 60 * 14 = 840 hrs
Work done by A in 1 hr = 1/840
B has same efficiency
=> Work done by B in 1 hr = 1/840
Work done by A in 4 days = (1/840)(5 + 6 + 7 + 8) = 26/840 = 13/420
Work done by A in 80 Days = (80/4) * (13/420) = 13/21
Work to be done by B = 1 - 13/21 = 8/21
Work done by B in 80 days = 8/21
Work done by B in 1 days = (8/21)/80 = 1/210
Work done by B in 1 hr = 1/840
Work done by B in x Hrs = x/840
=> x/840 = 1/210
=> x = 4
B has to work 4 hrs daily
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