Math, asked by anjujoseph652, 11 months ago

A can do a piece of work in 80 days and B in 100 days. They work together for 20 days and then B gone away. In how many days will A finish the remaining work?

Answers

Answered by Durgesh12345
13

Answer:44 days

Step-by-step explanation:

In one day A does the work of 1/80

And B 1/100

If they work for 20days then total work done is

20/80+20/100=1/4+1/5

=9/20

Remaining work=1-9/20=

=11/20

In one day A does 1/80

So time required to do the 11/20 work is 11/20/(1/80)=11/20*80=11*4

=44

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