If the sides of a triangle are in the ratio of 3:4:5 and area is 216cm2. Find perimeter of triangle.
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let the side a be 3x
let the side b be 4x
let the side c be 5x
area of triangle = 216
3x + 4x + 5x = 216
12x = 216
x = 216/12
x = 18
side a = 3x = 3×18 = 54cm
side b = 4x = 4×18 = 72cm
side c = 5x = 5×18 = 90cm
PERIMETER OF TRIANGLE = a +b + c
= 54+72+90= 216
let the side b be 4x
let the side c be 5x
area of triangle = 216
3x + 4x + 5x = 216
12x = 216
x = 216/12
x = 18
side a = 3x = 3×18 = 54cm
side b = 4x = 4×18 = 72cm
side c = 5x = 5×18 = 90cm
PERIMETER OF TRIANGLE = a +b + c
= 54+72+90= 216
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