Question

A can do a piece of work in 80 days. he works at it for 10 days and then be alone finishes the remaining work in 42 days . in how much time will a and b working together ,finish the work

Answer 1

50 will be the answer

Answer 2

Work done by a in single day=W/80
In 10 days it will be =W/8
Therefore B has to do 7/8 work
7/8Wtake 42days
W take 42*8/7=48 days
Let they together take x days
x(W/80+W/48)=W
x=30 days
Hope it helps
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