Question

A bullet of mass 10g travelling horizontally with a velociy of 160m/s strikes a stationary wooden block and comes to rest in 0.02s . the distance of penetration of the bullet into the block will be

Answer 1

acce=v/t=160/0.02=8000m/s^2
v^2=2as
160*160=2*8000*s
s=1.6 m

Answer 2

Answer: is 1.6m

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