Math, asked by gayatri8293, 1 year ago

A can do a piece of work in 80 days . he works at it for 10 days and then b alone finishes the remaining work in 42 days .in how much time will And B working together finish the work​

Answers

Answered by ritesh275
5

Ajay can do part of park in 1 day=1/80

Work done by ajay in 10 days=10/80

=1/8

Remaining work=1-1/8

=7/8

B complete in 42 days=7/8part of work

B can complete in1day=1/48part of work

So B alone can complete it in 48 days

Work done by both in 1 day

=1/80+1/48

=(3+5)/240

=1/30

So they can finish the work together in 30days


ritesh275: please mark as brainlist
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