Question

A can do a piece of work in 9 days and B can do it in 6 days. With the help of C, they can finish the work in 3 days. Then , C alone can do the work in

a-18 days
b-20 days
c-24 days
d-12 days
​

Answer 1

Answer:

a) 18 days

Step-by-step explanation:

1 day's work of:-

A= 1/9

B = 1/6

let, time taken for C to complete the work alone be x.

1 day's work of C = 1/x

ATQ:

$\frac{1}{9} + \frac{1}{6} + \frac{1}{x} = \frac{1}{3} \\\\ \frac{2+3}{18} + \frac{1}{x} = \frac{6}{18} \\\\ \frac{1}{x} = \frac{6}{18} - \frac{5}{18} = \frac{1}{18} \\\\x = 18$

Therefore, C can alone do the work in 18 days.

Answer 2

Answer:

here's the answer. your answer is 18 days means C's work =1/18= work done in 1 day = 18days