a can do a piece of work in 9 days B is 50% more efficient than a the number of 8 days take by b to do the same piece of work is
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Working capacity of B = A + 50% of A
= 1 + ½ of A
= 3/2 of A
Time taken by A to complete the job = 9 days
Time taken by B to complete the job = time taken by 3/2 of A to complete the job ( proved above)
=> A = 9 days
=> 3/2 of A = 9 days * 2/3
=> 3/2 of A = 6 days
=> B = 6 days
Ans. = The time taken by B to complete the job is 6 days.
Hope it helps!!!!
Mark me brainliest if the answer is correct ^^"
= 1 + ½ of A
= 3/2 of A
Time taken by A to complete the job = 9 days
Time taken by B to complete the job = time taken by 3/2 of A to complete the job ( proved above)
=> A = 9 days
=> 3/2 of A = 9 days * 2/3
=> 3/2 of A = 6 days
=> B = 6 days
Ans. = The time taken by B to complete the job is 6 days.
Hope it helps!!!!
Mark me brainliest if the answer is correct ^^"
Yuichiro13:
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ab kya hua
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