A can do a price of work in 25days which B can alone do In 20days. A started the work and was joined by B after 10days. In how many days was the work done?
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Answer:
Let B worked for n Days along with A.
- A = 25 Days
- B = 20 Days
• According to the Question :
⇒ Days/A + Days/B = Total Work
⇒ (10 + n)/25 + n/20 = 1
⇒ [4(10 + n) + 5n]/100 = 1
⇒ 40 + 4n + 5n = 100
⇒ 9n = 100 - 40
⇒ 9n = 60
⇒ n = 60/9
⇒ n = 20/3
⇒ n = 6⅔ Days
• Total Days Taken to Complete Work :
⇒ 10 + 6⅔ Days
⇒ 16⅔ Days
∴ They completed work in 16⅔ Days.
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