A can do a work in 10 days and B can do it in 15 days. They worked together for 4 days and then A left the work. In how many days can B finish the remaining work? If the remuneration of the work is one thousand rupees, how much amount would each person get?
Answers
Answer:
A( 10 )
B(15)
total unit of work = 30
for 1 day,
A = 3*4 = 12
B = 2
so,
remaining work = 30-12 = 18
B = 2 unit = 1day
= 1 unit = 1/2day
= 18 unit = 18/2
= 9 days
so,
1 day = 1000
9 days = 9*1000= 9000rup
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Correct Question: A can do a work in 10 days and B can do it in 15 days. They worked together for 4 days and then A left the work. In how many days can B finish the remaining work? If the remuneration of the work is one thousand rupees per day, how much amount would each person get?
Given: Number of days taken by A to do the work alone = 10 days
Number of days taken by B to do the work alone = 15 days
Number of days A and B worked together = 4 days
To find: The number of days B takes to finish the remaining work after A leaves and their remunerations
Solution: According to the given question,
Time taken by A to finish the work = 10 days
Time taken by B to finish the work = 15 days
Work done by A in 1 day =
Work done by B in 1 day =
Work done by A and B together in 1 day =
Work done by them together in 4 days = =
The remaining work = i.e.,
(to be done by B alone)
Now, work is done by B in 1 day
∴ work will be done by him in
days = 5 days
Thus, B takes 5 days to finish the remaining work.
Now, given that remuneration of the work is Rs. 1,000 per day
Number of days A worked = 4
Number of days B worked = 4 + 5 = 9
∴ A's remuneration =
∴ B's remuneration =
Hence, B finishes the remaining work in 5 days and gets Rs. 9,000 as remuneration and A's remuneration is Rs. 4,000.