Question

Find the point on x axis which are distance of 5 unit from.The point a(5-3)

Answer 1

AS IT IS ON X-AXIS, THE CORDINATE WILL BE P(x,0), and other cordinate is (5,-3),

BY DISTANCE FORMULA,

5= √(x₂-x₁)²+(y₂-y₁)²

on squaring both sides,

⇒25 = (x-5)²+(0+3)²

⇒25 = x²+25-10x + 9

⇒x²-10x+9=0

⇒x²-x-9x+9

⇒x(x-1)-9(x-1)

⇒(x-1)(x-9)

AS THERE ARE TWO VALUES OF X=1 AND 9...SO

THE CORDINATES ARE: (1,0) AND (9,0)