A can do a work in 12 days, B can do the same work in 15 days and C in 20 days. B started the work alone. A joined 3 days after B started the work and Cjoined 2 days after A joined. In how many days the work was completed?
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Answer:
may be, 2 weeks? nice to answer
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Step-by-step explanation:
A can finish a work in 12 days, and B can do it in 15 days. After I had worked for 3 days, we also join A to finish the remaining part of the body. In how many days the work will be finished?
LCM of 12 and 15 =60
Hence consider the quantum of work to be 60 units.
A can finish the job of 60 units in 12 days.. ..Hence, per day A does 5 units of work.
Similarly, B does 4 units of work per day.
For 3 days, A does the job alone…..which means he completes 5*3=15 units of work.
Hence balance work remaining = 60–15 = 45 units
A and B combined can finish (5+4)=9 units of work per day.
They will take 45 units / 9 units/day =5 days to complete the remaining work.
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