Math, asked by biswajitchatterjee46, 1 year ago

A can do a work in 15 days .a and b together can complete the work in 12 days. b alone can do it

Answers

Answered by Anonymous
1

Heya....

Here's your answer.....



A and B → 12 days


A → 15days


So, let's take LCM of 15 and 12. That's 60.

This 60 unit is the total work to be done.


So, A and B do (60/12) = 5 unit work/day …(1)


And, A does (60/15) = 4 unit work/day …(2)


(1)-(2) gives


B does (5–4)= 1 unit/day


So, Total days req. = (Total work)/unit per day


i.e, B can do it in (60/1)=60 days.



Thanks...!!!

XD

Sorry baby 'wink'

Answered by anuragpandeyuna
0

Here is your answer

A do 1/15 part of work in one day

A+b do in 12 day

A+b do work in one day =1/12 part of work

1/15+b =1/12

B=5-4/60 [on taking lcm 12 and 15]

B =1/6o part of work in one day

B=60 day

So,b takes 60 days

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