Math, asked by himanshukumar5925, 11 months ago

A can do a work in 15 days and b can do it in 18 days. With the help of c, all of them complete the work in 6 days. A, b and c received total rs.27,000 for the whole work. What is the share of c, if the money is distributed in the ratio of amount of work done, individually?

Answers

Answered by subrataana9349
0

Answer:

Step-by-step explanation:

A can do a piece of work in 15 days while B can do it in 20 days. They work together for 6 days and the remaning work is done by C in 2 days. If they get Rs. 6500 for the whole work, what will be the B's share?

Let the Whole work be ‘1″

A takes 15 days to complete the whole work, hence A completes 1/15th of the work in 1 day.

B takes 20 days to complete the whole work, hence B completes 1/20th of the work in 1 day.

In one day A and B can together complete 1/15th+1/20th of the work, adding it up will make 7/60.

A’s work for 6 days will be 6*1/15=6/15. Similarly B’s work for 6 days will be 6/20

For 6 days the work will be 6/15+6/20=42/60.

Now, the remaining work is completed by C, Remaining work will be “Whole work less work completed by A and B together.”

That will be equal to 1–42/60, simplifying it further C has done here 18/60 of the work.

Now, Ratio between A, B and C’s work here will be 6/15:6/20:18/60, Make the denominators equal to 60. A’s work is 6/15*4/4=24/60. B’s work is 6/20*3/3=18/60.

Ratio between A, B and C will be = 24/60:18/60:18/60.

Now, A’s share of 6,500 = 6,500*24/60=2600

Similarly B’s Share = 6,500*18/60 = 1850

Similarly C’s Share = 6,500*18/60 = 1850

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