Question

A can do a work in 15 days and B in 30 days. If they work togather, how much time will A and B take to complete the work?​

Answer 1

Answer:

Step-by-step explanation:

A can finish work alone in 15 days, So, A’s 1 day work =  $\frac{1}{15}$

B can finish work alone in 30 days, So, B’s 1 day work = $\frac{1}{30}$

Amount of work finished by A and B together in 1 day will be sum of work done individually,

Hence, (A+B)’s 1 day work = $\frac{1}{15} + \frac{1}{30}$

$=\frac{45}{430}$

$=\frac{1}{10}$

There fore, number of days required to complete the work will be reciprocal of 1 day’s work.

Number of days required for (A + B) =  10  days

Answer 2

Answer:

10 days

Step-by-step explanation:

The process is as follows :

Person A can finish the work alone in 15 days. So, A’s 1 day work =  1/15.

Person B who can finish his/her work alone in 30 days. That means B’s usual day of work is 1/30.

The total amount of work finished by Person A and Person B together in 1 day will be the sum of work done individually!

Therefore, Person A + Person B's day of work = (1/15) + (1/30)

Which is simplified into

1/10

Hence, the number of days required to complete the work will be the reciprocal of a day's work.

That means the number of days required for Person A + Person B is 10 days.

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