a can do a work in 20 days and b in 15 days and c in 15 days if they work together how many days
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Given A can do the work in 20 days and B can do it 15 days.
Then work done by A in one day =201
And, work by B in one day =151
Then, the work done by A & B in one day =201+151=607
A & B done 6 days together then work done in A & B in 6 days =607×6=107
Then friction of work left =1−107=103
Then B can do 103 work =103×115=29=421 days
HreidevKR:
Thank you so much
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