Math, asked by sandhumanveer3421, 1 year ago

A can do as much work b ad c together can do a and b in 9 hrs 36 min and c can do in 48 hrs

Answers

Answered by venky14800
0

Answer:

Step-by-step explanation:

9 hours 36 minutes =

= 9+\frac{36}{60} = 9\frac{3}{5}\ hours = \frac{48}{5}\ hours

(A + B)’s 1 hour’s work = \frac{5}{48}

C’s 1 hour’s work = \frac{1}{48}

(A + B + C)’s 1 hour’s work = \frac{5}{48} + \frac{1}{48} =  \frac{1}{8}…………(I)

A’s 1 hour’s work = (B + C)’s 1 hour’s work…………(II)

From equation (I) and (II),

2\times(A’s 1 hour’s work) = \frac{1}{8}

A’s 1 hour’s work = \frac{1}{16}

∴ B’s 1 hour’s work =  \frac{5}{48} - \frac{1}{16}

= \frac{5-3}{48} = \frac{1}{24}

∴ B alone will finish the work in 24 hours.

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