A can do as much work b ad c together can do a and b in 9 hrs 36 min and c can do in 48 hrs
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Answer:
Step-by-step explanation:
9 hours 36 minutes =
= 9+\frac{36}{60} = 9\frac{3}{5}\ hours = \frac{48}{5}\ hours
(A + B)’s 1 hour’s work = \frac{5}{48}
C’s 1 hour’s work = \frac{1}{48}
(A + B + C)’s 1 hour’s work = \frac{5}{48} + \frac{1}{48} = \frac{1}{8}…………(I)
A’s 1 hour’s work = (B + C)’s 1 hour’s work…………(II)
From equation (I) and (II),
2\times(A’s 1 hour’s work) = \frac{1}{8}
A’s 1 hour’s work = \frac{1}{16}
∴ B’s 1 hour’s work = \frac{5}{48} - \frac{1}{16}
= \frac{5-3}{48} = \frac{1}{24}
∴ B alone will finish the work in 24 hours.
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