A can do some work in 10 days.B is 50% more efficient than a then in how many days b alone can do the same work?
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b alone Can do the work in 6 2/3 days
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Let the total work unit =1unit
A can finish in 10 days=1 unit
A's 1 day work=1/10units
B's 1 day work=1/10+(50/100)×1/10=3/20units
so,B can do 1 unit in 1/3/20=20/3=6.67 days or 6 2/3 days
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