Math, asked by akanshasrivastav15, 1 month ago

A can do some work in 24 days, B can do it in 32
days and C can do it in 60 days. They start working
together. A left after 6 days and B left after working
for 8 days. How many more days are required to
complete the whole work?
(a) 30
(c) 22
(b) 25
(d) 20
(explain in detail)​

Answers

Answered by Anonymous
0

Answer:

In 1 day A works 1/24 parts

in 1 day B works 1/32 parts

in 1 day C works 1/60 parts

They work together for 6 days. So in 1 day they work (1/24+1/32+1/60) parts

= 43/480 parts

So in 6 days they do 43/80 parts

Now parts of work left = 1- 43/80= 37/80

And B and C work together for 8 days

B and C work in 1 day= 1/32+1/60=23/480 parts

B,C in 8 days do= 23/60 parts

Now balance work= 37/80 - 23/60= 19/240 parts

This part of the world be done by C alone

C does 1 work in 60 days

C in 19/240 parts in 60*19/240 days= 19/4 days

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