Question

A can done work in 10 days, B in 12 days
then A , B work together But After5 days A left
How many recquired for B to complete the work?​

Answer 1

Answer

Given,

• 'A' can do a work in 10 days
• 'B' can do the same work in 12 days
• 'A' and 'B' worked together for 5 days

To find,

Days required for 'B' to complete the remaining work.

Now,

Let us first find out one day work of both 'A' and 'B'

(We need to have one day work in such type of questions)

One day work of 'A' = $\rm \frac { 1 } { 10 }$

One day work of 'B' = $\rm \frac { 1 } { 12 }$

Work that 'A' and 'B' can together do in one day :

$\implies \rm \frac { 1 } { 10 } + \frac { 1 } { 12 }$

Work that 'A' and 'B' can together do in 5 days :

$\implies \rm 5(\frac { 1 } { 10 } + \frac { 1 } { 12 })$

$\implies \rm 5( \frac { 5 + 5 } { 60 } )$

$\implies \rm \frac { 10 } { 12 }$

Now let 'B' will take 'x' days to complete the remaining work.

In 'x' days 'B' will do$</u></strong><strong><u>\rm </u></strong><strong><u>\frac </u></strong><strong><u>{ </u></strong><strong><u>x</u></strong><strong><u> </u></strong><strong><u>} </u></strong><strong><u>{ </u></strong><strong><u>12</u></strong><strong><u> </u></strong><strong><u>} </u></strong><strong><u>$ work.

Total work will surely be '1'

So,

Total work = Work done together + work done by 'B' alone.

1 = $\rm \frac { 10 } { 12 } + \frac { x } { 12 }$

$\rm 1 = \frac { 10 + x } { 12 }$

Cross multiplying it,

$\implies \rm 10 + x = 12$

$\implies \rm x = 2$

Hence 'B' will take 2 days to complete the remaining work.

Answer 2

Answer:

2 day s

Step-by-step explanation:

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