Math, asked by sunil8264, 11 months ago

A can end the work in 12 days, but B is 60% more efficient than A. How long will it take for B to do the same.​

Answers

Answered by ayushmanjaiswal
0

Answer:

7.5 days

Step-by-step explanation:

Let, Total Work Unit = 120 Units

>> A can finish in 12 days = 120 unit work

i.e. A can finish in 1 days = 10 unit work

i.e. B can finish in 1 days = 10+(60/100)*10 = 16 unit work

>> Days in which B will complete the work alone = 120/16 = 30/4 = 7.5 days

Answered by Manmohan36
0

60 % of 12

=60/100×12

=7.2

So time taken by B = 12-7.2

=4.8 days

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