A can end the work in 12 days, but B is 60% more efficient than A. How long will it take for B to do the same.
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Answered by
0
Answer:
7.5 days
Step-by-step explanation:
Let, Total Work Unit = 120 Units
>> A can finish in 12 days = 120 unit work
i.e. A can finish in 1 days = 10 unit work
i.e. B can finish in 1 days = 10+(60/100)*10 = 16 unit work
>> Days in which B will complete the work alone = 120/16 = 30/4 = 7.5 days
Answered by
0
60 % of 12
=60/100×12
=7.2
So time taken by B = 12-7.2
=4.8 days
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