Question

A can finish a piece of work in 36 days B is 10% less efficient than A , C is 20% less efficient than B . In how many days B and C can finish the same piece of work?

Answer 1

A------36 DAYS
B------36-36×10/100=32.4 days
C------32.4-32.4×20/100=25.92 days

Answer 2

Hi Friend!

I will explain In short=>

There is someone known as A and he has to do some work. He can complete that work in 36 days. There is another person be who is 10% weak than A and he could complete the day in some days more than A as he is a little weak. There is another person C who is 20% weaker than B and he can finish the work in more days.

We have to find the days.

So let us find the days of work can be completed by B

so 10% of 36 
=1/10*36
=3.6 days

So B will finish the work in
36+3.6
=39.6
= 40 days (estimated to nearest tens)


Now lets see of C's number of days

30% of 36 (20% +10% of B to compare the days with A)

3/10*36
=10.8 days

So,
36+10.8
= 46.8 
=47 days (estimated to nearest tens)


I hope this helped you!

Please mark it as Brainliest if you liked it ^-^

Regards,

crystinia
<Ace>