Question

A can finish a piece of work in 48 days. he worked alone for 8 days and then b joined him. together they could finish the remaining work in 16 days. in how many days b alone can finish the same piece of work ?

Answer 1

this will help you I think so

Answer 2

Answer:

B can complete work in 32 days alone.

Step-by-step explanation:

A can finish a piece of work in 48 days.

A's 1 day work = $\frac{1}{48}$

A's 8 days work = $\frac{1}{48}\times 8 = \frac{1}{6}$

Remaining work = $1-\frac{1}{6}= \frac{5}{6}$

They worked together and completed the work in 16 days = $\frac{5}{6}$

They worked together and completed the work in 1 day = $\frac{\frac{5}{6}}{16}$

A's 1 day work = $\frac{1}{48}$

So, B's 1 day work =  $\frac{\frac{5}{6}}{16}-\frac{1}{48}$

                               =  [tex]\frac{1}{[32}/tex]

So, B can complete whole work in days = 32

Hence B can complete work in 32 days alone.