A can finish a work in 18 days and B can do the same work in 5 days B worked for 10 days and left the job in how many days a alone can finish the remaining work a can finish a work in 18 days and B can do the same work in 5 days B worked for 10 days and left the job in how many days a alone can finish the remaining work
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It must be 2× 18 = 36 days.
Hriday0102:
I m not sure of my answer. but I tried to help u. Sorry if it is wrong
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A can finish 1/18th of the total work in a day and B can finish 1/15th of the total work in a day. After working 10 days by B alone,the work remains is 1−1015=131−1015=13th of the total work.
It can be finished by A in13÷118=1×183×1=613÷118=1×183×1=6days.
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Right answer but i am not getting that how it comes 6 days
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