A can finish a work in 18 days and b can do the same work in 15 days. b worked for 10 days and left the job. in how many days, a alone can finish the remaining work?
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Answered by
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Work done by B in 10 days = 10 * 1/15
= 2/3.
Work left = 1 - 2/3
= 1/3.
Hence A alone can finish the remaining work in 18 * 1/3 = 6 days.
Hope this helps!
= 2/3.
Work left = 1 - 2/3
= 1/3.
Hence A alone can finish the remaining work in 18 * 1/3 = 6 days.
Hope this helps!
Answered by
1
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