A can finish a work in 20 days while b can finish it in 12 days . A started the work alone and after 4 days b join him and they worked together till the work was completed
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Work by A in 1 day = 1/20
Work by B in 1 day = 1/12
Together they work = (1/20)+(1/12) = (3 + 5)/60 = 8/60 = 2/15
Total time taken by them = 7.5 days
But here A work 5 days alone.
Work by A in 5 days = (3/60)×5 = 15/60
Let x be the number of days they work after.
After that they work together,
(15 + × (3+8))/60 = 1
8x = 60 - 15
x = 45/8
x = 5(5/8) days
Total time taken = 5 + 5 (5/8) = 10 (5/8)days
Work by A in 1 day = 1/20
Work by B in 1 day = 1/12
Together they work = (1/20)+(1/12) = (3 + 5)/60 = 8/60 = 2/15
Total time taken by them = 7.5 days
But here A work 5 days alone.
Work by A in 5 days = (3/60)×5 = 15/60
Let x be the number of days they work after.
After that they work together,
(15 + × (3+8))/60 = 1
8x = 60 - 15
x = 45/8
x = 5(5/8) days
Total time taken = 5 + 5 (5/8) = 10 (5/8)days
Humanoid:
but I have written the correct answer 10 days
Answered by
1
solution :
total work : 60 units
A. B. A+B
3. 5. 8
A worked for 4 days = 4 * 3 = 12 units
remaining units = 48
A +B worked for x days to complete remaining units
= 48/8 days
= 6 days
so A + B took 6 days to complete remaining work
total days taken to complete job = 6+4 = 10 days
hope that helps!!!!
PLEASE MARK AS BRAINLIEST
total work : 60 units
A. B. A+B
3. 5. 8
A worked for 4 days = 4 * 3 = 12 units
remaining units = 48
A +B worked for x days to complete remaining units
= 48/8 days
= 6 days
so A + B took 6 days to complete remaining work
total days taken to complete job = 6+4 = 10 days
hope that helps!!!!
PLEASE MARK AS BRAINLIEST
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