A car travelling at a speed of 30 km/h is brought to rest in a distance of 8 m by applying brakes.If the same car is moving at a speed of 60km/h then it can be brought to rest with same brakes in
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Stopping distance s =
here u =30km/h
s = 8m
u'=2(30) which is 60km/h given in question
now s' becomes
new stopping distance s' will be
4(8) = 32m
here u =30km/h
s = 8m
u'=2(30) which is 60km/h given in question
now s' becomes
new stopping distance s' will be
4(8) = 32m
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