A can finish a work in 24 days, B in 9 days, and C in 12 days. B and C started the work but are forced to leave after 3 days. In how many days is the remaining work done by A. please explain dont give direct answer
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Answer:B+C)'s 1 day's work =(
9
1
+
12
1
)=
36
7
Work done by B and C in 3 days =(
36
7
×3)=
12
7
Remaining work =(1−
12
7
)=
12
5
Now,
24
1
work is done by A in 1 day.
So,
12
5
work done by A in (24×
12
5
)=10 days.
Step-by-step explanation:
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