Question

A can finish work in 18 days b can do in 15 days.B worked for 10 days and left the job how many daysa alone finish the job

Answer 1

Step-by-step explanation:

$work \: done \: by \: a \: in \: 1 \: day \: = \frac{1}{18} \\ work \: done \: by \: b \: in \: 1 \: day \: = \frac{1}{15} \\ work \: done \: by \: b \: in \: 10 \: days \: = \frac{1}{15} \times 10 = \frac{2}{3}$

$work \: left \: = 1 - \frac{2}{3} = \frac{1}{3} \\ days = \frac{ \frac{1}{3} }{ \frac{1}{18} } \\ days \: = \frac{18}{3} = 6$

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