Question

A cancave mirror produces 10 cm long image of an object of height 2 cm. What is the magnificent produced ?​

Answer 1

Height of image (h¡)= 10cm {Negative}

Height of object (h°)= 2cm {Positive}

So,

Magnification(m) = h¡/ h°

m = -10/ 2

m = -5

Therfore image wile be 5 times the object and will be real and inverted.

Answer 2

Answer

Height of image(-v)= -10 cm

Height of Object(u)= +2 cm

Magnification (m) =$\frac{-v}{u}$ $\frac{height of image}{Height of object}$

$\frac{-10}{2}$

$= - 5$

Hope This Helps You

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