A candidate got 56500 votes in an election and won by his opponent by a margin of 3000 votes. If there were only two candidates, find the percentage of votes obtained by the defeated candidate.
Answers
Answered by
17
Votes of winning candidate=56500
Votes of losing candidate=56500-3000
=53500(As winner won by a margin of 3000 which means that by 3000 more votes than the loser)
Total votes=56500+53500=110000
Percentage= required quantity÷total quantity ×100%
=
Votes of losing candidate=56500-3000
=53500(As winner won by a margin of 3000 which means that by 3000 more votes than the loser)
Total votes=56500+53500=110000
Percentage= required quantity÷total quantity ×100%
=
SakshiGC:
I can't understand
see my ans
it's incorrect
then what is correct
it's incorrect we will not subtract 3000 from the votes of the winning candidate
and the total no of votes polled are 59500
winner is ahead by 3000 votes
Similar questions