a candidate score 25% marks in an examination and failed by 30 marks while another candidate who scored 50% marks got 20 marks more than the minimum pass marks Find the maximum marks and minimum pass marks
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Here is the solution:
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Find the difference in percentage:
50 - 25 = 25%
Find the difference in marks:
30 - (-20) = 50 marks
Find the maximum marks:
25% = 50 marks
1 % = 50 ÷ 25 = 2 marks
100% = 2 x 100 = 200 marks
Find 50% of the marks (second candidate's marks):
50% of the marks = 50% x 200 = 100 marks
Find the minimum marks to pass:
The candidate passed by 20 marks
100 - 20 = 80 marks
Answer: 200 is the maximum marks and the minimum marks to pass is 80.
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