Question

A candidate score 30% fails by 5 marks while another candidate who score 40%gets 10 more than minimum pass mark. The minimum marks required to pass are
1) 150
2) 100
3) 70 4) 200
5) 50​

Answer 1

Answer:

5) 50

Step-by-step explanation:

let total marks are x and passing marks be y

30%of x = y - 5.

40%of x = y +10

40%of x - 30%of x =(y+10) - (y- 5)

10%of x = y+10 - y + 5

10%of x = 15

x = 150

passing marks = (30%of 150) + 5

45 + 5 = 50

Answer 2

$\huge \fbox \colorbox{olivedrab}{heya}$

let total Mark's be = x

first candidate

=

$30\% \: of \: x = \frac{3x}{10}$

minimum pass mark =

$\frac{3x}{10} + 5$

.................(1)

second candidate =

$40\% \: of x = \frac{4x}{10}$

minimum pass mark

$\frac{4x}{10} - 10$

.......................(2)

( he scores 10 mark more than minimum)

ATQ

$\frac{3x}{10} + 5 = \frac{4x}{10} - 10$

$= \frac{3x}{10} - \frac{4x}{10} = - 10 - 5$

$= \frac{ - x}{10} = - 15$

$= x = 150$

minimum pass Mark's =

$\frac{3 \times 150}{10} + 5$

( using 1)

= 50

hence the required answer is 50

⭐at end :

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