- A candidate scored 25% marks in an examination and failed by 30 marks, while another candidate
who scored 50% marks got 20 marks more than the minimum pass marks. Find the minimum pass
marks and the maximum marks.
ice cream yendor has yanilla and chocolate ice creams in the ratio of 4: 9. If there are 100
Answers
Answer:The Answer is
Step-by-step explanation:
Let the maximum marks be 'x'.
Then, according to the question.
(25 % of x) + 30 = (50 % of x) - 20
⇒ x/4 + 30 = x/2 - 20
⇒ (x/4) - (x/2) = - 20 - 30
⇒ (x - 2x)/4 = - 50
⇒ - x/4 = - 50
⇒ - x = - 200
⇒ x = 200
So, the maximum marks are 200.
Minimum passing marks are = x/4 + 30
= 200/4 + 30
= 50 + 30
= 80 marks
Minimum passing marks are 80.
#MrcJoc
Answer:
80 marks
Step-by-step explanation:
Let the maximum marks be 'x'.
Then, according to the question.
(25 % of x) + 30 = (50 % of x) - 20
⇒ x/4 + 30 = x/2 - 20
⇒ (x/4) - (x/2) = - 20 - 30
⇒ (x - 2x)/4 = - 50
⇒ - x/4 = - 50
⇒ - x = - 200
⇒ x = 200
So, the maximum marks are 200.
Minimum passing marks are = x/4 + 30
= 200/4 + 30
= 50 + 30
= 80 marks