Question

A candidate scored 25% marks in an examination and failed by 30 marks, while another candidate who
scored 50% marks got 20 marks more than the minimum pass marks. Find the maximum marks and
minimum pass marks.
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Answer 1

Answer:

Step-by-step explanation:

Solution:-

Let maximum marks be x

Minimum marks to pass =25% of x+30=4x​+30

Now according to question,

4x​+30=2x​−20

2x​−4x​=30+20

⇒x=50×4=200

Hence the maximum marks to be obtained are 200.

Now, minimum passing marks =4200​+30=80

Hence the maximum marks to be obtained are 200 and the minimum passing marks are 80.

Answer 2

answer:

passing marks=

25%+30=50%-20

30+20=50%-25%

50=25%

The passing marks

=25%+30

=50+30

=80

full marks=100×50/25

=200

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