Question

Triangle ABC is isosceles with right angle at vertex B . If AC=10 cm then AB=​

Answer 1

Answer:

10

Step-by-step explanation:

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Answer 2

Answer:

AB=5√2cm

Step-by-step explanation:

In ∆ABC ,

angle B=90°

therefore ∆ ABC is right angled triangle

AC^2=AB^2+BC^2. ... {Pythagoras theorem}

but AB=BC. ......{ given}

let AB=BC=X

10^2=X^2+X^2

100=2X^2

100/2=X^2

50=X^2

X=5√2

therefore AB=5√2 cm