Question

A candidate scoring 20% in an examination fails by 30 marks while another candidate who scores 45% marks gets 20 marks more than the minimum marks required for a pass. Find the minimum pass percentage​

Answer 1

Answer:

Let the maximum pass marks be x

20% of x + 30 = 45% of x - 20

20/100x+30=45/100x−20

20x+3000 = 45x-2000

25x = 5000

x = 5000/25=200

Maximum marks = 200

Minimum pass marks = 20/100×200+30=40+30=70

Answer 2

Hlo my veer g ur answer is here ✌️☺️

let the maximum pass marks be x

20% of x+30= 45% of x -20

20/ 100 x +30 = 45/100 x-20

20x + 3000 = 45x - 2000

25 = 5000 x

x = 5000/25 = 200

so the minimum pass marks = 20/100*200 +30 = 40+30 = 70.

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