A star moves away from earth at speed 0.8 c while emitting light of frequency 6 × 10¹⁴ Hz . What frequency will be observed on the earth (in units of 1014 Hz) (c = speed of light)
(a) 0.24
(b) 1.2
(c) 30
(d) 3.3
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Answered by
2
I think the answer is option (b).
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Answer: (b) 1.2
Explanation:
Given data
A star moves away from earth.
speed = 0.8 c m/s
emitting light of frequency =6 × 10^14 Hz .
c = speed of light = 3*10^8 m/s
To find:
frequency will be observed on the earth (in units of 10^14 Hz)
We know that,
v' = v(1-v/c)
where v = emitted frequency
v'= observed frequency
Putting values in formula we get
v'= 6 × 10^14 * (1- (0.8c) /c)
= 6 × 10^14 * 0.2
= 1.2*10^14Hz
=1.2( in units of 10^14 Hz)
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