A cannon launches a 3.0 kg pumpkin with 110 J of kinetic energy.
Answers
Answered by
1
Answer:
v=8.56[m/s]
Explanation:
The kinetic energy can be calculated by means of the following equation.
E_{k}=\frac{1}{2}*m*v^{2}E
k
=
2
1
∗m∗v
2
where:
m = mass = 3 [kg]
v = velocity [m/s]
Ek = kinetic energy [J]
\begin{gathered}110 = \frac{1}{2} *3*(v^{2} )\\v^{2} = 220/3\\v=\sqrt{73.333}\\v=8.56[m/s]\end{gathered}
110=
2
1
∗3∗(v
2
)
v
2
=220/3
v=
73.333
v=8.56[m/s]
Answered by
1
Answer:
bzbsndneneje
Explanation:
ndndjdkdd
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