Question

a cannon of weight 10 tonnes fires a shell of 50 kg with a muzzle velocity of 900 m/sec at an angle of 30. the time taken for the shell to emerge from the barrel is 0.004 sec. the velocity of cannon would be

Answer 1

Answer:

3.9 m/s

Explanation:

Given :

A cannon of weight 10 tonnes fires a shell of 50 kg with a muzzle velocity of 900 m/s at an angle of 30°.

The time taken for the shell to emerge from the barrel is 0.004 sec.

The velocity of cannon would be ..

Solution :

Statement 1 :

A cannon of weight 10 tonnes fires a shell of 50 kg with a muzzle velocity of 900 m/s at an angle of 30°.

We know that,

⇒ Muzzle velocity in x - axis ,

⇒ 900 × cos 30° = $900 \times \frac{\sqrt{3}}{2} = 450\sqrt{3} = 450 \times 1.732$ ≈ 779.4 m/s

Since , movementum is conserved ,

⇒ MV = mv

⇒ 10,000 × V = 50 × 779.4

⇒ $V = \frac{50 \times 779.4}{10,000} = \frac{38,970}{10,000} = 3.897m/s$ ≈ 3.9 m/s