Question

A cannon standing on the top of a cliff, 40 m high fires a cannon ball horizontally out to sea
with a muzzle speed of 140 m/sec. How far out to sea does the ball go?
(A) 242.8 m
(B) 262.8 m
(C) 272.8
(D) 282.8 m


Please solve this question in detail​

Answer 1

Given that,

Height = 40 m

Speed = 140 m/s

We need to calculate the time

Using equation of motion

$s=ut-\dfrac{1}{2}gt^2$

Where, u = initial velocity

g = acceleration due to gravity

t = time

Put the value into the formula

$-40=0-\dfrac{1}{2}\times10\times t^2$

$t^2=\dfrac{40\times2}{10}$

$t=\sqrt{\dfrac{40\times2}{10}}$

$t=2\sqrt{2}\ sec$

We need to calculate the distance covered by the ball

Using formula of speed

$v=\dfrac{d}{t}$

$d=v\times t$

Where, v = speed of ball

t = time

Put the value into the formula

$d=140\times2\sqrt{2}$

$d=280\sqrt{2}\ m$

$d=395.9\ m$

According to option,

Option D is nearest to answer

Hence, The distance covered by the ball is 282.8 m.

Answer 2

Answer:

d 282.8

Explanatio