Question

A capacitor having capacitance of 5uF is charged to a potential difference of 10,000 V. The energy stored in the capacitor is?

Answer 1

Given:

Capacitance (C) = 5 μF

Potential difference (V) = 10000 V

To find:

Energy stored in the capacitor

Solution:

• Energy stored in the capacitor (E) = $\frac{1}{2}$CV²

                                                                 = $\frac{1}{2}$ × 5 × $10^{-6}$ × 10000 × 10000

• E = 250 J

Answer 2

Answer:

A capacitor having a capacitance of 5uF is charged to a potential difference of 10,000 V. The energy stored in the capacitor is $250\ J$

Explanation:

• Let C be the capacitance and V be the potential difference between the capacitor plates.
• Then, electric potential energy (E) stored in the capacitor  can be expressed as,

            $E=\frac{1}{2} C V^{2}$    ...(1)

In the question, it is given that,

$V= 10,000\ V$

$C =5\ \mu F = 5\times10^{-6} F$

Substitute these  values into equation (1)

$E=\frac{1}{2}\times 5\times10^{-6} \times 10,000^{2} = 250\ J$

Thus,

The energy stored in the capacitor   will be $250\ J$